Organic Chemistry Practice Problems and Problem Sets
up-down-kick carbonyl mechanism
The overall mechanism for imine formation is shown below. (This isn't a real mechanism, just an outline)
Use curved arrows to draw the full mechanism for imine formation under acidic conditions. (I've added outlines of the intermediate structures for you to use as a guide). This mechanism is similar to that in problem 706 (carbonyl hydrate equilibria).
This reaction takes place under acidic conditions, so oxygen should never be negative (only neutral or positively charged).
Acidic mechanisms tend to be a bit of pain, because you have to include many proton transfer steps (protonation and deprotonation).
MendelSet practice problem # 707 submitted by Matt on July 22, 2011.
Carbonyls are in equilibrium with their hydrate forms. This equilibrium happens in both acid and base.
Let's go through this equilibrium under acidic conditions. Draw a mechanism using curved arrows for each reaction below.
Remember that under acidic conditions, most species are either neutral or positively charged, and rarely negatively charged. So your structures will contain either ROH or ROH2+, but not RO-.
a) Carbonyl to Hydrate (acidic)
b) Hydrate to Carbonyl (acidic)
The interconversion between a carbonyl (sp2 carbon) and a tetrahedral intermediate (sp3 carbon) is the most common mechanism you will encounter in second semester organic chemistry.
You should be familiar drawing it under both acidic (this problem) and basic (problem 705) conditions.
In a), the carbonyl "goes up" to form a tetrahedral intermediate.
In b), an oxygen "comes back down" to reform the carbonyl and kick off a leaving group.
You will see this "up, down, kick" pattern in most mechanisms that involve attack at the carbonyl carbon, which is most of the reactions in second semester orgo!
a) Carbonyl to Hydrate (acidic) "UP"
Because this reaction takes place under acidic conditions, the carbonyl must protonate before the nucleophile attacks, to prevent oxygen from ever being negative (ROH instead of RO-).
b) Hydrate to Carbonyl (acidic) "DOWN"
The leaving group must protonate before it leaves, so it doesn't leave as a negative molecule (H2O instead of HO-).
MendelSet practice problem # 706 submitted by Matt on July 22, 2011.
Carbonyls are in equilibrium with their hydrate forms. This equilibrium happens in both acid and base.
Let's go through this equilibrium under basic conditions. Draw a mechanism using curved arrows for each reaction below.
Remember that under basic conditions, most species are either neutral or negatively charged, and rarely positively charged. So your structures will contain either ROH or RO-, but not ROH2+.
a) Carbonyl to Hydrate
Notice that no oxygen is ever positive during these basic mechanisms (always negative or neutral).
b) Hydrate to Carbonyl
The mechanisms in this problem and problem 706 are the most common mechanisms you will draw during second semester organic chemistry, and so it's a good idea to draw them out a few times.
In a), the nucleophile attacks the carbonyl carbon, and the double bond goes "up" to form a tetrahedral (sp3) carbon.
In b), one of the oxygen atoms acts as leaving group, and a lone pair on the other oxygen comes "down" to reform the double bond (and the sp2 carbon).
You will see this "up, down, kick" pattern in most mechanisms that involve attack at the carbonyl carbon, which is most of the reactions in second semester orgo!
a) Carbonyl to Hydrate (basic conditions) "UP"
b) Hydrate to Carbonyl (basic conditions) "DOWN"
MendelSet practice problem # 705 submitted by Matt on July 21, 2011.