Write the structure of the major organic product of each reaction.
a) is a free-radical bromination. The radical will be formed at the most stable position, which will be the allylic position due to resonance (see problem 569). There are two allylic positions in this molecule, so the more substituted one will be the more stable; the bromine will add to the 3º allylic carbon.
b) is an E2 reaction. There are two types of beta protons and so two possible alkene products. One is an isolated diene and the other is a conjugated diene. Conjugated dienes are more stable, and so that will be the major product.
MendelSet practice problem # 571 submitted by Matt on July 8, 2011.
Write out the mechnanism for the formation of the 1,2 and 1,4 products of the reaction below.
This is an SN1 reaction, but the carbocation is special because it's allylic.
If the Br- nucleophile attacks the 3º resonance form, the 1,2 product is formed. (This is the product that would have formed if resonance was not involved.)
If the Br- nucleophile attacks the 2º resonance form, the 1,4 product is formed.
MendelSet practice problem # 572 submitted by Matt on July 8, 2011.
Let's work through a 1,2 and 1,4 addition. Draw the structures for each of the species in the six boxes below. Also draw curved arrows to show electron movement.
This is an SN1 reaction, but with a twist.
The top reaction is a regular SN1 reaction; the leaving group (Br-) leaves and the nucleophile (CH3OH) attacks the carbocation.
The twist is that the carbocation is allylic, and has resonance, so there is another carbon that the nucleophile can attack.
So instead of just one SN1 product, two products are formed. The product that doesn't involve resonance is called the direct addition or 1,2 product. The product that involves allylic resonance is called the conjugate addition or 1,4 product.
MendelSet practice problem # 522 submitted by Matt on July 1, 2011.